Answer:
Explanation:
There are two heat flows in this process and, since energy (heat) can neither be destroyed nor created, the energy change for the system must equal zero.
Data:
For Fe, m₁ = ?; C₁ = 0.452 J°C⁻¹g⁻¹; Ti = 2.00 °C; T_f = 21.50 °C
For H₂O, m₂ = 120 g; C₂ = 4.18 J°C⁻¹g⁻¹; Ti = 22.00 °C; T_f = 21.50 °C
Calculations:
1. Temperature changes
ΔT₁ = T_f - Ti = 21.50 °C - 2.00 °C = 19.50 °C
ΔT₂ = T_f - Ti = 21.50 °C - 22.00 °C = -0.50 °C
2. Mass of steel rod
Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
ΔT = 1,86°C/m · 0,122 m.
ΔT = 0,226°C.
Answer:
Ribosomes preform biological synthesis. (mRNA Translation). They also link amino acids together to form polypeptide chain.
iron salts react with water to form hydrated iron ( III ) oxide which is basically rust
hope that helps :)
D. 2.2 pounds would be the answer
