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2 years ago

If during an experiment zinc was found to be more reactive than lead or copper, zinc would be considered the strongest _____.

Chemistry

1 answer:

densk [106]2 years ago

5 0

Zinc would be considered the strongest reducing agent.

<h3>Reducing agent</h3>

A reducing agent is a chemical species that "donates" one electron to another chemical species in chemistry (called the oxidizing agent, oxidant, oxidizer, or electron acceptor). Earth metals, formic acid, oxalic acid, and sulfite compounds are a few examples of common reducing agents.

Reducers have excess electrons (i.e., they are already reduced) in their pre-reaction states, whereas oxidizers do not. Usually, a reducing agent is in one of the lowest oxidation states it can be in. The oxidation state of the oxidizer drops while the oxidizer's oxidation state, which measures the amount of electron loss, increases. The agent in a redox process whose oxidation state rises, which "loses/donates electrons," which "oxidizes," and which "reduces" is known as the reducer or reducing agent.

Learn more about reducing agent here:

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Answer:

$-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}$

Explanation:

The rate law of a chemical reaction is given by

$-r_{A}=k\times[BF_3]^{\alpha}\times[NH_3]^{\beta}$

This law can be written for any experiment, and making the quotient between those expressions the reaction orders can be found

Between experiments 1 and 2

$\frac{-r_{A1}}{{-r}_{A2}}=\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)^\beta$

Then the expression for the calculation of $\beta$

$\beta=\frac{ln\frac{-r_{A1}}{-r_{A2}}}{ln\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)}=\frac{ln\frac{0.2130}{0.1065}}{ln\left(\frac{0.250}{0.125}\right)}$

Resolving

$\beta=1$

Doing the same between experiments 3 and 4 the expression for $\alpha$ is

$\alpha=\frac{ln\frac{-r_{A3}}{-r_{A4}}}{ln\left(\frac{\left[BF_3\right]_3}{\left[BF_3\right]_4}\right)}=\frac{ln\frac{0.0682}{0.1193}}{ln\left(\frac{0.200}{0.350}\right)}$

Resolving

$\alpha=1$

This means that the rate law for this reaction is

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