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aliya0001 [1]
2 years ago
7

The electrophilic bromination or chlorination of benzene requires ______ along with the halogen.

Chemistry
1 answer:
Oksanka [162]2 years ago
8 0

The electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.

<h3>What is bromination of benzene?</h3>

The bromination or chlorination of benzene is an example of an electrophilic aromatic substitution reaction.

During the reaction, the bromine forms a sigma bond to the benzene ring, yielding an intermediate. Subsequently a  a proton is removed from the intermediate to form a substituted benzene ring.

This reaction is achieved with the help of Lewis acid as catalysts.

Thus, the electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.

Learn more about bromination of benzene here: brainly.com/question/26428023

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Please Help Me!!!
sergejj [24]

Answer:

The products are carbon dioxide and water

Explanation:

Step 1: Data given

Combustion = a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve  O2  as one reactant.

Step 2: The complete combustion of C3H7OH:

For the combustion of 1-propanol, we need O2.

The products of this combustion are CO2 and H2O.

C3H7OH + O2→ CO2 + H2O

On the left side we have 3x C (in c3H7OH), on the right side we have 1x C (in CO2). To balance the amount of C, we have to multiply CO2 on the right side by 3

C3H7OH + O2→ 3CO2 + H2O

On the left side we have 8x H (in C3H7OH) and 2x on the right side (in H2O). To balance the amount of H, we have to multiply H2O, on the right side by 4.

C3H7OH + O2→ 3CO2 + 4H2O

On the left side we have 3x O (1x in C3H7OH and 2x in O2), on the right side we have 10x O (6x in CO2 and 4x in H2O).

To balance the amount of O on both sides, we have to multiply C3H7OH by 2, multiply O2 by 9. Then we have to multiply 3CO2 by 2 and 4H2O by 2. Now the equation is balanced.

2C3H7OH + 9O2→ 6CO2 + 8H2O

For 2 moles propanol, we need 9 moles of O2 to produce 6 moles of CO2 and 8 moles Of H2O

The products are carbon dioxide and water

7 0
3 years ago
An object was measured by a worker as
marusya05 [52]
<h2>Answer - 0.73%</h2>

14.6            .2

          =          

100              x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

6 0
3 years ago
Read 2 more answers
This is not a homework question
Dovator [93]
What state you live in? because I know someone who does it for free
8 0
3 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
3 years ago
What is the volume of .750 M hydrochloride acid required to react completely with 25.00 mL of .290 M NaOH solution?
Whitepunk [10]

Explanation:

lease please please please please please please

8 0
3 years ago
Read 2 more answers
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