Hello,
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
![P_A=2(b+h) \\ P_A=2*[6+(x+2)] \\ P_A=2*(x+8) \\ P_A=2x+16 \\ \\ \\ P_B=2(b+h) \\ P_B=2*[3+(2x+1)] \\ P_B=2*(2x+4) \\ P_B=4x+8 ](https://tex.z-dn.net/?f=P_A%3D2%28b%2Bh%29%20%5C%5C%20P_A%3D2%2A%5B6%2B%28x%2B2%29%5D%20%5C%5C%20P_A%3D2%2A%28x%2B8%29%20%5C%5C%20P_A%3D2x%2B16%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20P_B%3D2%28b%2Bh%29%20%5C%5C%20P_B%3D2%2A%5B3%2B%282x%2B1%29%5D%20%5C%5C%20P_B%3D2%2A%282x%2B4%29%20%5C%5C%20P_B%3D4x%2B8%0A)
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.
The second one $50 per week
$500 divided by 10=50
If a quadrilateral is a parallelogram, then consecutive angles are supplementary. If a quadrilateral is a parallelogram, then opposite angles are congruent. If a quadrilateral is a parallelogram, then opposite sides are congruent. If a quadrilateral is a parallelogram, then the diagonals bisect each other.
2 lines are skew if they are neither parallel, nor intersecting.
If 2 lines are parallel or intersecting, they form a plane, so they are coplanar. So "skew" is the opposite or complement of "coplanar".
i) a and b: are both on M so coplanar, not skew
ii) b is in M, c is in N and they have no common point, so skew. (if they had a common point that would be a point in the line d of intersections of planes M and N, but they dont meet at such a point)
iii) b and e: are both on M so coplanar, not skew
iv) e and c : skew, same argument as ii.
v) a and e : are both on M so coplanar, not skew
vi) a and c: a is in M, c is in N. If they met, they would met at a point on line d, the only set of points common to planes M and N, but they dont. so skew
Answer:
84ft squared
Step-by-step explanation:
