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MakcuM [25]
3 years ago
14

One number is 8 more than the other. When the larger is divided by the smaller, the quotient is 7/5

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

<h3>          The numbers are 20 and 28</h3>

Step-by-step explanation:

x  - the other number  (the smaller one)

x+8  - 8 more than the other number (the larger number)

 

\dfrac{x+8}x=\dfrac75\\\\(x+8)\cdot5=x\cdot7\\\\5x+40=7x\\^{\quad-40\qquad-40}\\{}\quad5x = 7x-40\\^{\quad-7x\quad-7x}\\-2x=-40\\^{\div(-2)\quad\div(-2)}\\{}\ \ x=20\\\\x+8=28

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Can i please get help with this Question?
sashaice [31]

So firstly, I'm going to be converting the mixed number into an improper fraction. To do this, multiply the whole number by the denominator and then add that product with the numerator and that will be your new numerator. In this case:

3 × 8 = 24, 24 + 3 = 27. \frac{-27}{8}

Now since they have the same denominator, you can subtract the numerators.

\frac{-27}{8}-\frac{7}{8}=\frac{-34}{8}

Now simplify the number as such:

\frac{-34}{8}\div\frac{2}{2}=\frac{-17}{4}

<u>In short, your answer is -17/4, or -4 1/4.</u>

3 0
3 years ago
An equation that is true when y=-0.5
KIM [24]
2y+1=0.5+y.

Hope this helps!
3 0
3 years ago
R
Wittaler [7]

i have no idea what question you need answered

7 0
3 years ago
Read 2 more answers
!!!PLEASE HELP ASAP!!! <br> I WILL GIVE MORR POINTS IF NEEDED AND MARK BRAINLIEST
Firlakuza [10]
The first one shows 1 cm and 7 mm, we need to convert 7 mm to cm
1 cm + 7 mm
= 1 cm + \frac{7}{10} cm
= 1 cm + 0.7 cm
= 1.7 cm
The first one is 1.7 cm

The second one shows 11 inches and 5/16 inches. Between number 11 and 12, there are 16 strips and the pointer lies on fifth strip, thus it show 5/16 inches. The second one is 11\frac{5}{16} inches.

The third one shows 13 cm and 8 mm. We need to convert mm into cm.
13 cm + 8 mm
= 13 cm + 0.8 cm
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The third one is 13.8 mm
7 0
3 years ago
Start with the logistic equation dx dt kx(M−x). Suppose we modify our harvesting. That is we will only harvest an amount proport
Marina CMI [18]

Answer:

a) dx/dt = kx*(M - h/k - x)

Step-by-step explanation:

Given:

- The harvest differential Equation is:

                            dx/dt = kx*(M-x)

Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In  other  words  we  harvest hx per  unit  of  time  for  some h > 0

Find:

a) Construct the differential equation.  

b) Show that if kM > h, then the equation is still logistic.

c) What happens when kM < h?

Solution:

- The logistic equation with harvesting that is proportional to population is:

                               dx/dt = kx*(M-x) hx

It can be simplified to:

                              dx/dt = kx*(M - h/k - x)

- If kM > h, then we can introduce M_n=M -h/k >0, so that:

                              dx/dt = kx*(M_n  - x)  

Hence, This equation is logistic because M_n >0

- If kM < h,  then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n  - x)  < 0 for all x<0 then the population will tend to zero for all initial conditions

6 0
3 years ago
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