Answer:
is equidistant from a focus point and a line
Answer:

Step-by-step explanation:
The systems of equations are
Let us assume the rate of the current be c
Now actual speed against the current is (15 - c)
And, the actual speed with the current is (15 + c)
Here we applied the time formula i.e. distance by speed
Also the upstream time - downstream time = 4
Now the equations are

Answer:
maybe 11.2-9.6n...sorry if I get it wrong
Step-by-step explanation:
1500(1+0.04)^3 = 1687.30
1687.30(1+0.05) = 1771.67 to the nearest pound: 1772