Question

An archer shoots a 150. gram arrow straight up in the air. (Do not try this at home.) The bow was drawn back 75.0 cm by a 175 N force. How high does the arrow rise assuming air friction is negligible

Answer 1

Answer:

The arrow rise 44.64 m high assuming air friction is negligible

Explanation:

According to the law of conservation of energy

Kinetic energy =  Potential energy at highest

$\frac{1}{2}kx^2=mgh$----1

We know that F=kx

So,$k = \frac{F}{x}\\k=\frac{175}{0.75}$

Substitute the value in 1

$\frac{1}{2}(\frac{175}{0.75})(0.75)^2=0.15 \times 9.8 \times h\\\frac{\frac{1}{2}(\frac{175}{0.75})(0.75)^2}{0.15 \times 9.8}=h\\44.64 = h$

Hence  the arrow rise 44.64 m high assuming air friction is negligible