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4 years ago

If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.

Physics

2 answers:

hoa [83]4 years ago

8 0

Answer:

Melting

Explanation:

If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as:

freezing. NO. Freezing is the process in which a liquid turns into a solid.

vaporizing. NO. Vaporizing is the process in which a liquid turns into a gas.

condensing. NO. Condensing is the process in which a gas turns into a liquid.

melting. YES. Melting is the process in which a solid turns into a liquid.

tatiyna4 years ago

4 0

When something gets to hot it reaches its melting point, meaning it melts. the the answer would be D melting

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A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear

Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

$f_o = f_s\frac {(v+vs)}{v}$ and $f_o = f_s\frac {(v-vs)}{v}$ when moving towards observer

With $f_o$ of 76 then taking speed in air as 343 m/s we have

$76 = f_s\times\frac {(343-vs)}{343}$

$f_s=\frac {343\times 76}{343-v_s}$

Similarly, with $f_o$ of 65 we have

$65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}$

Now

$f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}$

v_s=27.76 m/s

Substituting the above into any of the first two equations then we obtain

$f_s=70.07 Hz$

4 0

3 years ago

A loop circuit has a resistance of R1 and a current of 1.9 A. The current is reduced to 1.5 A when an additional 3.1 Ω resistor

Deffense [45]

Answer:

11.625 Ohm

Explanation:

Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:

V/R1 = 1.9 or V = 1.9R1

After the resistor addition to series R = R1 + 3.1

I = V/R = V/(R1 + 3.1) = 1.5

We can substitute V = 1.9R1

1.9R1 = 1.5R1 + 1.5*3.1

0.4R1 = 4.65

R1 = 4.65/0.4 = 11.625 Ohm

4 0

4 years ago

Match the term with its description.

Mrac [35]

A=Ion

B=pH

C=Acid

D=Alkaline

6 0

3 years ago

A car moving with an initial speed of 25 m/s slows down to a speed of 5 m/s in 10 seconds Calculate a) the acceleration of the c

stealth61 [152]

Answer :

(a) The acceleration of the car is, $-2m/s^2$

(b) The distance covered by the car is, 150 m

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

$5m/s=25m/s+a\times (10s)$

$a=-2m/s^2$

The acceleration of the car is, $-2m/s^2$

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = $-2m/s^2$

Now put all the given values in the above equation 2, we get:

$s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2$

By solving the term, we get:

$s=150m$

The distance covered by the car is, 150 m

8 0

3 years ago

What is the deflection of a spring? A ball of mass 2kg is dropped from a height if 20cm on a spring of stiffness k=1225 N/m. Fin

ollegr [7]

Use the law of conservation of energy. Potential energy of the object with mass m at the height h is equal to:

 E=mgh

 and the potential energy of a spring is equal to Espring=1/2kx^2 where k = spring constant, x = displacement Since all the gravitational potential energy will be transformed to the spring potential energy, its quite easy to figure out the displacement from this two equations

E= mgh
E= 2*9.8*0.2
E= 3.92

E=1/2kx^2
E=1/2*1225*X^2
3.92*2=1225*X^2
0.0064=X^2
X=0.08 m or 8 cm

6 0

3 years ago