Line segment GH is divided by point J in the ratio of 1:4. Endpoint G is at (7,5) and point J is at (10, 14).
1 answer:
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Answer:
0.2611 = 26.11% probability that exactly 2 calculators are defective.
Step-by-step explanation:
For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
5% of calculators coming out of the production lines have a defect.
This means that
Fifty calculators are randomly selected from the production line and tested for defects.
This means that
What is the probability that exactly 2 calculators are defective?
This is P(X = 2). So
0.2611 = 26.11% probability that exactly 2 calculators are defective.
Rise over run is -2/4 or simplified as -1/2
The second one is
The second one is