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Leviafan [203]
3 years ago
9

The transportation department is resurfacing 12.75 miles of roadways in Narvarro Country. The crew completes work on a 1/8-mile

section of roadway each hour. How many hours will it take to complete the resurfacing project
Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

102 hours

Step-by-step explanation:

That would be 12 3/4 divided by 1/8   hours

= 51/4 / 1/8

= 51 * 8 / 4

= 408 /   4

= 102 hours


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Students at a middle school are divided into 6th, 7th, and 8th grades. A random sample of 15 students from each grade is chosen.
Julli [10]

Answer:

B. Stratified random sample is the correct answer

4 0
2 years ago
Use the Law of Cosines to find the missing angle. In triangle FGH, HF = 16 ft, FG = 23 ft, and m∠F = 52°. Find the measure of f.
ivolga24 [154]
F = 18 ft.

The law of cosines states 
c² = a² + b² - 2ab cos C

Using our information, we have 
c² = 23² + 16² - 2(23)(16)cos 52
c² = 529 + 256 - 736cos 52
c² = 785 - 736cos 52
c² = 331.8732

Taking the square root of both sides, we have
c = √331.8732 = 18.22 ≈ 18
5 0
3 years ago
How can you tell a situation is exponential from a graph
igor_vitrenko [27]

Answer: You are usually multiplying

Step-by-step explanation: The graph usually curves and not straight.

6 0
3 years ago
If you have a demand function of Qd=48-9P and a supply function of Qs=-12+6P,
jenyasd209 [6]

Answer:

The equilibrium quantity is 26.4

Step-by-step explanation:

Given

Q_d = 48 - 9P

Q_s = 12 + 6P

Required

Determine the equilibrium quantity

First, we need to determine the equilibrium by equating Qd to Qs

i.e.

Q_d = Q_s

This gives:

48 -9P = 12 + 6P

Collect Like Terms

-9P - 6P = 12 - 48

-15P = -36

Solve for P

P = \frac{-36}{-15}

P =2.4

This is the equilibrium price.

Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:

Q_d = 48 - 9P

Q_d = 48 - 9 * 2.4

Q_d = 26.4

<em>Hence, the equilibrium quantity is 26.4</em>

7 0
3 years ago
rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

5 0
3 years ago
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