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3 years ago

Reena saves AED 400 from her salary. If this is 10% of her salary. What is her salary?

Mathematics

1 answer:

Vlad1618 [11]3 years ago

6 0

A) AED 4000
4000 x .10= AED 400 therefore 400 is 10% of 4000

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What polynomial can be simplified to a different of squares? 10a2+3a-3a-16

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$10a^2 +3a -3a -16 = 10a^2 -16 = (\sqrt{10}a +4 ) (\sqrt{10}a - 4 )$

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What is the missing step in sovling the inequality 5-8x < 2x + 3?

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Answer:

add 8x to both sides of the inequality

Step-by-step explanation:

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What does -(-5) equal/mean?

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

Please help me out solve it and tell me how you got that answer so I can understand please!

NikAS [45]

The solution for s in the given equation is $s = C-nD$

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation $D= \frac{C-s}{n}$ Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

$D= \frac{C-s}{n}$

To solve for s, first multiply both sides by n to clear the fraction

We get

$n\times D= n \times \frac{C-s}{n}$

Then,

$nD = C - s$

Now, add s to both sides

$nD + s= C - s+s$

$nD+s = C$

Then, subtract nD from both sides

$nD-nD+s = C-nD$

∴ $s = C-nD$

Hence, the solution for s in the given equation is $s = C-nD$

Learn more here: brainly.com/question/21406377

6 0

3 years ago