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3 years ago

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In a freefall skydive, a skydiver begins at an altitude of 10,000 feet. during a freefall, the skydiver drops toward earth towar

ds earth at a rate of 175 ft per second. the height of the skydiver from the ground can be modeled using the function H(t)=10,000-175t.
What is the domain of the function for this situation?

1 answer:

asambeis [7]3 years ago

7 0

Answer:

{ $t|0\leq t\leq 50$ }

Step-by-step explanation:

We are given that

In a freefall skydive, a skydiver begins at an altitude during free fall =10,000 feet

The skydiver drops towards earth at a rate=175 ft/s

The height of the skydiver from the ground can be modeled using the function

$H(t)=10000-175t$

We have to find the domain of the function for this situation.

When t=0

Then , $H(0)=10,000 feet$

From given graph we can see that the value of t lies from 0 to 50.

Therefore, the domain of the function for this situation is given by

{ $t|0\leq t\leq 50$ }

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motikmotik

Answer:

the correct answer is -8

Step-by-step explanation:

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3 years ago

A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d

Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

So

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

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4 years ago

Find a formula for the fourth degree polynomial p(x) whose graph is symetric about the y-axis, and which has a y-intercept of 0,

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<span>The base of a triangle exceeds the height by 9 feet. If the area is 180 square feet, find the length of the base and the height of the triangle.</span>

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4 years ago

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

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For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

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$L = 15 + 5$

$L = 20\ in$

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3 years ago