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SOVA2 [1]
3 years ago
13

Please I’m desperate and tell me how you did it

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0

Given:

Triangle EFG is similar to triangle HIJ.

To find:

The measure of side IJ.

Solution:

We know that, corresponding sides of similar triangles are proportional.

Triangle EFG is similar to triangle HIJ.

\dfrac{EF}{HI}=\dfrac{FG}{IJ}

Putting the given values, we get

\dfrac{7}{32}=\dfrac{4}{IJ}

7\times IJ=4\times 32

IJ=\dfrac{128}{7}

IJ=18.2857

IJ\approx =18.3

Therefore, the measure of side IJ is 18.3 units.

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This writing prompts is hard
Solnce55 [7]
A.) Simplifying the equation would lead you to 15x^2-3x+9

b.) You know your answer is correct because you're adding the two polynomials together. 9x^2+6x^2 is 1tx^2. Now you have 2x-5x and since the negative is bigger, you get -3x. Then 5+4 is 9. You have no like terms therefore your answer is 15x^2-3x+9
7 0
3 years ago
Rectangle ABCD was dilated to create rectangle A'B'C'D.
77julia77 [94]

The first thing we must do for this case is to calculate the scale factor.

For this, we make the relationship between two parallel sides.

We have then:

k =\frac{B'C'}{BC}

Substituting values we have:

k = \frac{9.5}{3.8}\\k = 2.5

We are now looking for the value of AB

We have then:

AB = \frac{A'B'}{k}

Substituting values:

AB = \frac{15}{2.5}\\AB = 6

Answer:

The scale factor is:

k = 2.5

The value of AB is:

AB = 6

8 0
3 years ago
Read 2 more answers
I don't know number 10
yulyashka [42]
78500 is ur answer : ) : ) : )
3 0
3 years ago
Please solve this. im confused
jolli1 [7]
The answer is:

x = 5.3

3 0
2 years ago
If an area of a rectangle with width x can be represented with the expression A(x)=x(14-x), what is the perimeter of the rectang
AlekseyPX
To solve for the perimeter first figure out the length and width from the formula of area for the rectangle
A = LxW
A = (14-X)•X
L = (14-X)
W = X
P = 2L + 2W
P = 2(14-X) + 2(X)
P = 28 - 2X + 2X
P = 28.
The perimeter of the rectangle is A. 28.
6 0
3 years ago
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