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qaws [65]
3 years ago
8

Pls help I’ve been stuck on this for a while

Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

Maybe 60

Step-by-step explanation:

I don't know just please guess sorry but can you mark as brainiest.

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On a piece of paper, draw a box plot to represent the data below. Then
777dan777 [17]
Since they are already in order you know the 22 and the 61 are the upper and lower extremes. To find the median you find the number that is in the middle which is 42. To find the lower quartile find the middle number starting from the first number and the number to the left of the median (22 and 36 in this case). The loser quartile is 25. To find the upper quartile, fine the middle number between the number to the right of the median and the last number (44 and 61 in this case.) the upper quartile is 57 you then just plot it and graph it

The work is attached

6 0
3 years ago
Help me I don't understand this ​
Lelechka [254]

Answer:

3.5 Inches of snow left on Friday Night

Step-by-step explanation:

On Monday there was no snow

On Tuesday there was 3 inches

On Wednesday 3 - 0.5 inches= 2.5 inches of snow

On Thursday 2.5 + 2.5 inches= 5 inches

On Friday 5 - 1.5 inches=3.5 inches

Therefore the answer is that the was 3.5 inches of snow Friday night

8 0
3 years ago
It costs $3 for a pack of 20 pencils. Find the cost per pencil.
Cerrena [4.2K]

Answer:

20/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Math question below!!​
nikdorinn [45]

Answer:

A

Step-by-step explanation:

x² - 4x - 5 = 0

x² - 5x + x - 5 = 0

x(x - 5) + (x -5) = 0

(x - 5)(x + 1) = 0

x - 5 = 0   ; x + 1 = 0

x = 5      ; x = -1

7 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
3 years ago
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