Answer:
0.333 is 1/3
0.666 is 2/3
Step-by-step explanation:
I used my head but you can use a calculator too.
Answer:
Incomplete question
Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.
a. Determine the pre-collision momentum of the ball.
b. Determine the post-collision momentum of the ball.
c. Determine the momentum change of the ball.
Answer:
A. 1.5353kgm/s
B. 1.6963kgm/s
C. 0.161kgm/s
Step-by-step explanation:
A. The pre-collision momentum of the ball = mass of ball × velocity of ball
Mass of ball = 57.5g = 0.0575kg
Velocity of ball = 26.7m/s
Pre-collision momentum of ball = 0.0575×26.7
= 1.5353kgm/s
B. Post collision momentum of the ball = mass of ball × velocity of ball after impact
Velocity of ball after impact = 29.5m/s
Post collision momentum of ball after impact = 0.0575×29.5
= 1.6963kgm/s
C. Momentum change of ball = momentum after impact - momentum before imlact
= 1.6963kgm/s - 1.5353kgm/s
= 0.161kgm/s
Answer:
x = 20
Step-by-step explanation:
Assuming you require the value of x
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
7x - 15 is an exterior angle of the triangle, thus
7x - 15 = x + 28 + 4x - 3 , that is
7x - 15 = 5x + 25 ( subtract 5x from both sides )
2x - 15 = 25 ( add 15 to both sides )
2x = 40 ( divide both sides by 2 )
x = 20
Y = x + 5A linear equation (in slope-intercept form) for a line perpendicular to y = -x + 12 with a y-intercept of 5.y = 1/2x - 5Convert the equation 4x - 8y = 40 into slope-intercept form.y = -1/2x + 5A linear equation (in slope-intercept form) which is parallel to x + 2y = 12 and has a y-intercept of 5.3x - y = -5A linear equation (in standard form) which is parallel to the line containing (3, 5) and (7, 17) and has a y-intercept of 5.y = -3x + 1A linear equation (in slope-intercept form) which contains the points (10, 29) and (-2, -7).y = -5A linear equation which goes through (6, -5) and (-12, -5).x = -5A linear equation which is perpendicular to y = 12 and goes through (-5, 5).y = 5A linear equation which is parallel to y = 12 and goes through (-5, 5).y = -x + 5A linear equation (in slope-intercept form) which is perpendicular to y = x and goes through (3, 2).y = -5xA linear equation (in slope-intercept form) which goes through the origin and (1, -5).x = 2A linear equation which has undefined slope and goes through (2, 3).y = 3A linear equation which has a slope of 0 and goes through (2, 3).2x + y = -9A linear equation (in standard form) for a line with slope of -2 and goes through point (-1, -7).3x +2y = 1A linear equation (in standard form) for a line which is parallel to 3x + 2y = 10 and goes through (3, -4).y + 4 = 3/2 (x - 3)A linear equation (in point-slope form) for a line which is perpendicular to y = -2/3 x + 9 and goes through (3, -4).y - 8 = -0.2(x + 10)<span>The table represents a linear equation.
Which equation shows how (-10, 8) can be used to write the equation of this line in point-slope form?</span>
