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wariber [46]
2 years ago
9

What is the area of this trapezoid?

Mathematics
1 answer:
navik [9.2K]2 years ago
8 0

Answer:

A = 32

Step-by-step explanation:

A = ½ (a + b) h

A = ½ (3 + 10) 4

A = (3+5)4

A = (8)4

A = 32

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8090 [49]

Answer:

4x+5x=180

It's D

7 0
3 years ago
Read 2 more answers
Look at the image below plz correct answers Surface area of cones 15 points
monitta

Answer:

A\approx 282.7\ m^2

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to use the Pythagorean theorem to find the height of the cone. Then one can substitute the values given and found on the cone into the formula to find the surface area in order to solve for the surface area of the given cone.

2. Height of the cone

Imagine drawing a line from the tip of the cone down to the center of the base. This line will form a right angle with the base, thus, a right triangle is formed between the line, the radius (the distance from the center to the circumference or outer edge on a circle) of the base, and the incline of the cone. The Pythagorean theorem is a formula that relates the sides of a right triangle. This formula is as follows:

a^2+b^2=c^2

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle, and (c) is the hypotenuse or the side opposite the right angle of the right triangle. Substitute the given values into the formula and solve for the unknown, or rather the height of the cone:

a^2+b^2=c^2

a^2+5^2=13^2

Simplify,

a^2+5^2=13^2

a^2+25=169

Inverse operations,

a^2+25=169

a^2=144

a=12

h=12

3. Find the surface area of the cone.

The following formula can be used to find the surface area of a cone:

A=\pi r(r+\sqrt{h^2+r^2})

Where (\pi) represents the numerical value (3.1415...), (r) represents the radius of the base, and (h) represents the height of the cone. Substitute the given values into the formula and solve for the surface area:

A=\pi r(r+\sqrt{h^2+r^2})

A=\pi 5(5+\sqrt{12^2+5^2})

Simplify,

A=\pi 5(5+\sqrt{12^2+5^2})

A=\pi 5(5+\sqrt{144+25})

A=\pi 5(5+\sqrt{169})

A=\pi 5(5+13)

A=\pi 5(18)

A=\pi 90

A\approx 282.743

3 0
3 years ago
What are the real and complex solutions of the polynomial equation X^3-216=0
vazorg [7]

Answer:

6,\ -3+3\sqrt{3}i,\ -3-3\sqrt{3}i

Step-by-step explanation:

Factor the equation x^3-216=0 using formula for difference of the cubes:

x^3-216=(x-6)(x^2+6x+36),

then

x-6=0\ or\ x^2+6x+36=0.

1. The equation x-6=0 has real solution x=6.

2. The equation x^2+6x+36=0 has negative discriminant D=6^2-4\cdot 36=36-144=-108, then it has two complex solutions

x_{1,2}=\dfrac{-6\pm 6\sqrt{3}i}{2}=-3\pm3\sqrt{3}i.

3 0
3 years ago
In the figure, triangle ABC is congruent to triangle ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what
snow_tiger [21]
Its 4:1 hope this helps you out.
5 0
3 years ago
Baseball Games
vladimir1956 [14]
I think it’s y 12 and x 5
7 0
2 years ago
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