Find the slope of the line that passes through the points (2, -5) and (3, -6)
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Answer:
The mean and standard deviation of Y is $6.56 and $2.77 respectively.
Step-by-step explanation:
Consider the provided information.
Let Y represent their profit on a randomly selected pizza with this promotion.
The company is going to run a promotion where customers get $2 off any size pizza.
Therefore,
So the mean will be reduced by 2.
If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.
Therefore
Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.
a. The probability that on a randomly selected day, the jail population
is greater than 750,000 is 20.1%
b. The probability that on a randomly selected day, the jail population is
between 600,000 and 700,000 is 43.2%
Step-by-step explanation:
The given is:
1. The average daily jail population in the United States is 706,242
2. The distribution is normal and the standard deviation is 52,145
3. We need to find the probability that on a randomly selected day,
the jail population is greater than 750,000
4. We need to find the probability that on a randomly selected day,
the jail population is between 600,000 and 700,000
a.
At first find z-score
∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard
deviation
∵ x = 750,000 , μ = 706,242 and σ = 52,145
∴ z = ≅ 0.84
Use the normal distribution table of z to find the area to the right of
the z-value
∵ The corresponding area to z-score of 0.84 is 0.79955
- But we are interested in x > 750,000, we need the area to the
right of z-score
∴ P(x > 750,000) = 1 - 0.79955 = 0.2005
∴ P(x > 750,000) = 0.2005 × 100% = 20.1%
The probability that on a randomly selected day, the jail population is
greater than 750,000 is 20.1%
b.
We will find z-score for 600,000 < x < 700,000
∵ z = ≅ -2.04
∵ z = ≅ -0.12
Use the normal distribution table of z to find the area between
the two z-values
∵ The corresponding area to z-score of -2.04 is 0.02068
∵ The corresponding area to z-score of -0.12 is 0.45224
- To find P(600,000 < x < 700,000) subtract the two values above
∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316
∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%
The probability that on a randomly selected day, the jail population is
between 600,000 and 700,000 is 43.2%
Learn more:
You can learn more about z-score in brainly.com/question/7207785
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