The price of a toy usually costs £50 is increased to £65 work out the percentage increase

a mischievous dog can eat 27 treats and 3 minutes how many treats can a dog eat in 8 minutes assuming he eats at the same rate

sukhopar [10]

27 treats per 3 minutes = 9 : 1
if the ratio is 9:1, multiply by 8, and you get
72 treats per 8 minutes

you're welcome!

7 0

2 years ago

Read 2 more answers

100 points.

7nadin3 [17]

Answer:

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

Step-by-step explanation:

hope this helps if does mark brainllest

6 0

1 year ago

PLEASE HELPPP i would really appreciate it :)

qaws [65]

Answer:

Y = - 12.55X1 + 276.52

Step-by-step explanation:

Given the data:

Age of child :(X) : 4, 6, 10, 13, 14, 17

Time (seconds) (Y) : 230, 205, 132, 119, 108, 62

Using technology, the linear regression equation obtained using the data Given is :

Y = - 12.55X1 + 276.52

Where :

Slope = - 12.55

Intercept = 276.52

This also indicates that a negative slope is present and hence a negative relationship between age of Child and time in seconds.

3 0

2 years ago

the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function

Likurg_2 [28]

The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about area here:

brainly.com/question/27683633

#SPJ4

3 0

1 year ago

which of the following could result in higher living costs for the homeowner that the renter doesnt have?

maw [93]

Well, Homeowners have to pay property taxes, maintnece fees, plus all utilities. Renters have to pay utilities and sometimes maintenance fees if the property does not have a property manager. Because a rental agent finds a tenant for a fee, a property manager takes care and collects rent for the absentee owner.
<span />

8 0

3 years ago

Read 2 more answers