All categories

3 years ago

The price of a toy usually costs £50 is increased to £65 work out the percentage increase

Mathematics

1 answer:

I am Lyosha [343]3 years ago

8 0

Answer:

Step-by-step explanation:

10% of 50 = 5

5% of 50 = 2.5

to get to 65 u do 5+5 = 10 so so far that is 20% but 20% only gets u to 60 so u add another 10% to reach 65

u have used 30% so the answer to yr question is 30%

<h2><em>does this help comment if / if not </em></h2>

You might be interested in

PLEASE HELP!!!

rosijanka [135]

Answer:

Area of the other polygon = 4 in.²

Step-by-step explanation:

Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon

Let "x" represent the area of the smaller polygon

Thus, we have:

100/x = 20²/4²

100/x = 400/16

100/x = 25

Cross multiply

25x = 100

Divide both sides by 25

25x/25 = 100/25

x = 4

Area of the other polygon = 4 in.²

8 0

3 years ago

39.54 divided by 3 please.

jeka57 [31]

Answer: 13.18

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the Distribution property of multiply addends of number,the add the products

KonstantinChe [14]

The address the products

5 0

3 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

3 0

4 years ago

20% of a restaurant customers order the chef’s special. 230 customers are anticipated to dine at the restaurant tonight. The sta

Serga [27]

Answer:

i don't knwo

Step-by-step explanation:

4 0

3 years ago