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Kay [80]
3 years ago
6

Can anybody solve this for me​

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Step-by-step explanation:

Square root of 25 can be +5 or -5

Square root of 16 can be +4 or -4.

As -5 can be square root of 25 and +4 can be a root of 16 , -5 < +4 . That's why square root of 25 could be less than square root of 16.

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A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
4 years ago
Would like scatter plot image with line of best fit on the plot
dlinn [17]

Just take it in co-ordinate pairs

  • (x,y)=(Arm span,Height)

Take two points

  • (58,60)
  • (41,40)

Slope:-

\\ \sf\longmapsto m=\dfrac{40-60}{41-58}

\\ \sf\longmapsto m=\dfrac{-20}{-17}

\\ \sf\longmapsto m=\dfrac{20}{17}

\\ \sf\longmapsto m\approx 1.2

Equation of line in point slope form

\\ \sf\longmapsto y-y_1=m(x-x_1)

\\ \sf\longmapsto y-60=1.2(x-58)

\\ \sf\longmapsto y-60=1.2x-69.6

\\ \sf\longmapsto 1.2x-y-9.6=0

  • Convert to slope intercept form y=mx+b

\\ \sf\longmapsto y=1.2x-9.6

Graph attached

7 0
3 years ago
The figure shown is a rectangle. If you draw a new rectangle in which the dimensions are doubled, what is the relationship betwe
KATRIN_1 [288]
the answer is A, sorry if you can't read it quite well

7 0
4 years ago
Which of the statements about the following quadratic equation is true?
Sedaia [141]
After manipulating above equation we get, 2x^2 - 7x - 8= 0. Discriminant= b^2 - 4ac = (-7)^2 - 4(2)(-8) = 113>0. So there are 2 real roots :)
3 0
4 years ago
Read 2 more answers
Solve the equation for a K = 4a + 9ab
Nuetrik [128]

Answer:

K/(4+9b) = a

Step-by-step explanation:

K = 4a + 9ab

Factor out a on the right hand side

K = a(4 + 9b)

Divide each side by (4+9b)

K/(4+9b) = a(4 + 9b)/(4+9b)

K/(4+9b) = a

3 0
3 years ago
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