is the size in wheels on the scale model .
<u>Step-by-step explanation:</u>
Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?
We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:
Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,
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{ x is size of wheel in scale model }
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Therefore , is the size in wheels on the scale model .
Answer:
you
Step-by-step explanation:
Recall that to get the x-intercepts, we set the f(x) = y = 0, thus
![\bf \stackrel{f(x)}{0}=-4cos\left(x-\frac{\pi }{2} \right)\implies 0=cos\left(x-\frac{\pi }{2} \right) \\\\\\ cos^{-1}(0)=cos^{-1}\left[ cos\left(x-\frac{\pi }{2} \right) \right]\implies cos^{-1}(0)=x-\cfrac{\pi }{2} \\\\\\ x-\cfrac{\pi }{2}= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bf%28x%29%7D%7B0%7D%3D-4cos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%5Cimplies%200%3Dcos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%280%29%3Dcos%5E%7B-1%7D%5Cleft%5B%20cos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%20%5Cright%5D%5Cimplies%20cos%5E%7B-1%7D%280%29%3Dx-%5Ccfrac%7B%5Cpi%20%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0Ax-%5Ccfrac%7B%5Cpi%20%7D%7B2%7D%3D%0A%5Cbegin%7Bcases%7D%0A%5Cfrac%7B%5Cpi%20%7D%7B2%7D%5C%5C%5C%5C%0A%5Cfrac%7B3%5Cpi%20%7D%7B2%7D%0A%5Cend%7Bcases%7D)
Answer:
The smaller number equals 12, the larger number equals 51.
Step-by-step explanation:
x + (3x + 15) = 63
Combine like terms.
4x + 15 = 63
Subtract 15 from both sides.
4x + (15 -15) = (63 - 15)
4x = 48
Divide both sides by 4.
4x/4 = 48/4
x = 12
Check answer.
12 + (3(12) + 15) = 63
12 + 36 + 15 = 63
63 = 63
Answer:
x = 16
y = 16 sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp/hyp
sin 60 = y/ 32
Multiply each side by 32
32 sin 60 = y
32 ( sqrt(3) /2) = y
16 sqrt(2)
cos theta = adj/ hyp
cos 60 = x /32
32 cos 60 = x
32 (1/2) =x
16 =x
