Answer:
<em>b. 0.6024</em>
Step-by-step explanation:
<u>Conditional Probability</u>
Suppose two events A and B are not independent, i.e. they can occur simultaneously. It means there is a space where the intersection of A and B is not empty:
If we already know event B has occurred, we can compute the probability that event A has also occurred with the conditional probability formula
Now analyze the situation presented in the question. Let's call F to the fair coin with 50%-50% probability to get heads-tails, and U to the unfair coin with 32%-68% to get heads-tails respectively.
Since the probability to pick either coin is one half each, we have
If we had picked the fair coin, the probability of getting heads is 0.5 also, so
If we had picked the unfair coin, the probability of getting heads is 0.32, so
Being A the event of choosing the fair coin, and B the event of getting heads, then
The closest answer is
b. 0.6024
Answer:
x <-14.5
Step-by-step explanation:
2x + 2(x+5) <+4(8 – 20)
Distribute
2x+2x+10 < 4 (-12)
4x +10 < -48
Subtract 10 from each side
4x+10-10 <-48-10
4x< -58
Divide each side by 4
4x/4 < -58/4
x <-14.5
Answer:
I only have 2
Step-by-step explanation:
each sides is multiplying by 2
each order is multiplying by 12
Answer:
5/6 is greater
Step-by-step explanation:
First obtain a common denominator for the fractions. Multiply the denominator of one fraction to the denominator of another and that is the denominator for the new fractions (54). Then multiply the denominator of one fraction to the numerator of the other one to obtain the new numerator. (e.g. 5*9=45 so 5/6 ->45/54) do this to the other fraction and you will see that 7/9 -> 42/54 and 45/54 is greater than 42/54 so 5/6 is greater .
Answer:
option B
Step-by-step explanation:
since DA and CB are equal and originate from same line segmnet, they are parallel, so angle D and angle C are equal, angle A and anfle B are equal and angle E is the same for both,
