Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
Answer:
6 - (-8)
is 6 + 8
Step-by-step explanation:
Answer:
Step-by-step explanation:
(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)
=2n*5n + 2n*6 -3*5n + (-3)*6
=10n² + 12n - 15n - 18
= 10n² -3n - 18
We need to solve -3x+4y=12 for x
Let's start by adding -4y to both sides
-3x+4y-4y=12-4y
-3x=-4y+12
x = (-4y+12)/-3
x= 4/3 y -4
Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1
1/4 x -1/3 y =1
1/4 (4/3 y -4) -1/3 y =1
Use the distributive property
(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1
1/3 y -1 - 1/3 y =1
Now combine like terms
(1/3y -1/3y) + (-1) =1
= -1
-1 = 1
Now add 1 to both sides
0=2
So there are no Solutions
The answer is C
I hope that's help Will :)
