25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
The figure on the left side shows the water level is at the 0.5 liter mark, ie half a liter.
1 liter = 1000 mL
0.5*1 liter = 0.5*1000 mL
0.5 liter = 500 mL
If you poured all the water into the jug on the right (without spilling), then the water level should reach the 500 mL mark. This is the small tickmark exactly halfway between the 400 and 600.
The answer to this question is 2197! Hope this helped :3
Answer: 8/27 cubic yards
Step-by-step explanation:
Volume of cube = side length ³
(2/3)³ = 2³ / 3³ = 8 / 27
