I'll assume the ODE is

Solve the homogeneous ODE,

The characteristic equation

has roots at
and
. Then the characteristic solution is

For nonhomogeneous ODE (1),

consider the ansatz particular solution

Substituting this into (1) gives

For the nonhomogeneous ODE (2),

take the ansatz

Substitute (2) into the ODE to get

Lastly, for the nonhomogeneous ODE (3)

take the ansatz

and solve for
.

Then the general solution to the ODE is

Answer:
x=8
RPS = 36
Step-by-step explanation:
QPS = 180
The two angles that form QPS
QPR + RPS = 180
7x+88 + 3x+12 = 180
Combine like terms
10x+100 =180
Subtract 100 from each side
10x = 180-100
10x = 80
Divide by 10
x =80/10
x = 8
RPS = 3x+12
= 3(8)+12
24+12
36
Answer:
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Answer:
g(x + 7) = 11x + 80
g(x) + g(7) = 11x + 83
Step-by-step explanation:
g(x + 7) = 11(x + 7) + 3 = 11x + 77 + 3 = 11x + 80
g(x) + g(7) = 11x + 3 + 11(7) + 3 = 11x + 3 + 77 + 3 = 11x + 83
Answer:
Step-by-step explanation:
The initial temperature difference of 72 -34 = 38 °F is reduced to a difference of 72 -41 = 31 °F after 35 minutes. The exponential term in the temperature expression could have the factor ...
(31/38)^(t/35) = e^(-kt)
Taking the natural log, we find ...
(t/35)ln(31/38) = -kt
k = ln(38/31)/35 ≈ 0.00581711
To the nearest thousandth, this is ...
k ≈ 0.006
Using this in the equation for temperature, we have ...
T = 72 -38e^(-0.006t)
Filling in the desired value for t (80), we find the turkey temperature after 80 minutes to be about
T = 72 -38e^(-.006×80) = 72 -38e^-.48 ≈ 48.49
T ≈ 48 °F
The value of k is about 0.006, and the turkey temperature is about 48 °F.