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almond37 [142]
3 years ago
12

What is the answer for this question please?​

Physics
1 answer:
DENIUS [597]3 years ago
3 0
I’m not that good at physics but i’m pretty sure b
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Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hum
lana66690 [7]

Answer: send the message underwater because a more dense medium would make the sound travel faster.

Explanation:

Dolphins communicate using compression waves - longitudinal waves. Longitudinal waves requires a medium to travel. A longitudinal wave transfers energy by the vibration of medium particles in the direction of the wave motion. Compression are the regions where density of the medium is higher and rarefaction is a low density region.

A longitudinal wave travels faster in a denser medium. It has maximum speed in solid and minimum in gas. Thus, to transfer message quickly to dolphin B., dolphin A should send the message underwater and not in air. This is because water has higher density than air. Molecules collide more quickly in water than in air and it takes less time for signal to travel.

3 0
3 years ago
A boat floats in water a. Archimedes b. Bernoulli c. Density d. Pascal e. Pressure
Ivenika [448]
The answer is Density !, Do you also need an example ?

Rate this the brainliest answer , Thank youuu !
7 0
3 years ago
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How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes
cricket20 [7]

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity g=9.81m/sec^2

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

8=2\times 3.14 \sqrt{\frac{l}{9.81}}

l=3.987m

So length of the pendulum will be 3.987 m

3 0
3 years ago
Pikes Peak near Denver, Colorado, has an elevation of 14,110 ft. Calculate the pressure at this elevation using three different
kramer

Answer:

a) P = 1240 lb/ft^2

b) P = 1040 lb/ft^2

c) P = 1270 lb/ft^2

Explanation:

Given:

- P_a = 2216.2 lb/ft^2

- β = 0.00357 R/ft

- g = 32.174 ft/s^2

- T_a = 518.7 R

- R = 1716 ft-lb / slug-R

- γ = 0.07647 lb/ft^3

- h = 14,110 ft

Find:

(a) Determine the pressure at this elevation using the standard atmosphere equation.

(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.

(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.

Solution:

- The standard atmospheric equation is expressed as:

                           P = P_a* ( 1 - βh/T_a)^(g / R*β)

                          (g / R*β) = 32.174 / 1716*0.0035 = 5.252

                            P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252

                            P = 1240 lb/ft^2

- The air density method which is expressed as:

                            P = P_a - γ*h

                            P = 2116.2 - 0.07647*14,110

                            P = 1040 lb/ft^2

- Using constant temperature ideal gas approximation:

                            P = P_a* e^ ( -g*h / R*T_a )

                            P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )

                            P = 1270 lb/ft^2

6 0
3 years ago
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Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy
ch4aika [34]

C longitudnal waves

4 0
3 years ago
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