The satellite exerts a force of 1900 N on the Earth
Explanation:
To answer this question, let's remind Newton's third law:
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
In this problem, we can identify:
The Earth as object A
The satellite as object B
This means that if we apply the law, the force that the Earth exerts on the satellite must be equal (in magnitude) and opposite (in direction) to the force the satellite exerts on the Earth.
Since the Earth exerts a force of 1900 N on the satellite, this means that the satellite also exerts a force of 1900 N on the Earth.
Learn more about Newton's third law:
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Answer:
A
Explanation:
Diffraction, as the waves spread out (specifically spread to the whole house) by passing the door.
Perpendicular acceleration:
F = ma
a = 4 / 2 = 2 m/s²
Perpendicular distance:
s = ut + 1/2 at²
s = 0 x 4 + 1/2 x 2 x 4²
s = 16 m
Horizontal distance:
s = ut
= 3 x 4
= 12 m
Total distance = √(12² + 16²)
= 20 m.
The distance of the galaxy is 32.86 Mpc.
Using the hubble law, v = H₀D where v = apparent velocity of galaxy = 2300 km/s, H = hubble constant = 70 km/s/Mpc and D = distance of galaxy.
Since we require the distance of the galaxy, we make D subject of the formula in the equation. So, we have
D = v/H₀
Substituting the values of the variables into the equation, we have
D = 2300 km/s ÷ 70 km/s/Mpc
D = 32.86 Mpc
So, the distance of the galaxy is 32.86 Mpc
Learn more about hubble law here:
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