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PilotLPTM [1.2K]
3 years ago
10

a tennis ball is thrown straight up at a speed of 40m/s and caught at the same level. calculate rhe maximum height reached by th

e ball​
Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

80m

Explanation:

time taken for stone to reach max-height is t=final velocity - intial velocity / acceleration due to gravity

t=v-u/g

where:

v=0 , u=40m/s ,g=-10m/so

: t=0-40/-10

t=4secs

: max-height reach=ut + 0.5gt²

=(40)(4)+(0.5)(-10)(4)I

=160-5(16)

=160-80

=<u>8</u><u>0</u><u>m</u>

Rudiy273 years ago
7 0

Answer:

81.6 m

Explanation:

Answer: 81.6 m.

The time it takes gravity to slow 40 m/s to zero when it teaches maximum height is

-v(initial) / -g = t

-40 m/s / -9.8 m/s^2 = 4.08 s

The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s.

So the distance d of maximum height is

d = v(avg)•t

d = 20 m/s • 4.08 s = 81.6 m.

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Explain why the model of this chemical reaction obeys the Law of Conservation of Matter. A) because there are the same number of
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Answer:

(A) because there are the same number of atoms of each element shown on both sides

Explanation:

The Law of conservation of mass says that in a reaction the matter of the products should be equivalent to the matter of the reactants and the mass of the system should remain constant over time.

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In this reaction, on both sides the same number of atoms of each element are present.

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if these are the same as edge, then these are the answers! :)

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Read 2 more answers
You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 76.2 kg hop on board for a ride
marin [14]

a) The spring constant is 12,103 N/m

b) The mass of the trailer 2,678 kg

c) The frequency of oscillation is 0.478 Hz

d) The time taken for 10 oscillations is 20.9 s

Explanation:

a)

When the two children jumps on board of the trailer, the two springs compresses by a certain amount

\Delta x = 6.17 cm = 0.0617 m

Since the system is then in equilibrium, the restoring force of the two-spring system must be equal to the weight of the children, so we can write:

2mg = k'\Delta x (1)

where

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k' is the equivalent spring constant of the 2-spring system

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k'=k+k=2k

Substituting into (1) and solving for k, we find:

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b)

The period of the oscillating system is given by

T=2\pi \sqrt{\frac{m}{k'}}

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T = 2.09 s is the period of oscillation

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Solving the equation for m, we find the mass of the trailer:

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c)

The frequency of oscillation of a spring-mass system is equal to the reciprocal of the period, therefore:

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f is the frequency

T is the period

In  this problem, we have

T = 2.09 s is the period

Therefore, the frequency of oscillation is

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d)

The period of the system is

T = 2.09 s

And this time is the time it takes for the trailer to complete one oscillation.

In this case, we want to find the time it takes for the trailer to complete 10 oscillations (bouncing up and down 10 times). Therefore, the time taken will be the period of oscillation multiplied by 10.

Therefore, the time needed for 10 oscillations is:

t=10T=10(2.09)=20.9 s

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