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Taya2010 [7]
3 years ago
14

Divide a six-sided polygon into triangles to find the sum of its interior angles.

Mathematics
2 answers:
mars1129 [50]3 years ago
7 0
The answer is C. 1080. i got this by multiplying 180 by 6.
Svetlanka [38]3 years ago
5 0
Hello, the answer would be C. 1080. Hope this helps you, i am a geometry teacher.
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3× - 4y =65 when u =4
sergey [27]
If Y=4 then X=27
hope this helps

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3 years ago
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I NEED HELP ASAP. BEFORE 4:00
sineoko [7]

Answer:

The measure of x = 45 degrees

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Use a system of linear equations with two variables and two equations to solve. A number is 9 more than another number. Twice
Troyanec [42]

9514 1404 393

Answer:

  (x, y) = (3, 12)

Step-by-step explanation:

Using the given variable definitions, we can write the equations ...

  y = x + 9

  2(x +y) = 30

__

Solving the second equation for y, we have ...

  y = 15 -x

Substituting this into the first equation gives ...

  15 -x = x +9

  6 = 2x . . . . . . . . . add x-9

  3 = x . . . . . . . . . . divide by 2

  y = 3+9 = 12 . . . . substitute into the first equation

The numbers are (x, y) = (3, 12).

4 0
2 years ago
How do you do 1 kilometers 125 meters - 375 meters
olga_2 [115]
1km is 1000 m
1000m+125m-375m=750m
8 0
3 years ago
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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