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Zielflug [23.3K]
2 years ago
10

PLEASE ANSWER FAST!!

Mathematics
2 answers:
Masja [62]2 years ago
4 0
The answer to this is 12
sleet_krkn [62]2 years ago
4 0

Answer:

12

Step-by-step explanation:

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Dari data berikut tentuka median ( nilai tengah):
Andrej [43]
First, put the numbers in order
A. 1,2,3,4,5,7,8,8,9.....median (middle number) is 5..when there is an odd number of data values, there will only be one median.
B. 14,14,15,16,17,18,19,20....if there is an even number of data points, there will be 2 middle numbers. In that case, u add the 2 middle numbers and divide by 2 to find the median. (16 + 17) / 2 = 33/2 = 16.5 is ur median.
7 0
3 years ago
Simplify: 4.16-1.1*2.6+0.7 squared
ser-zykov [4K]

Answer:

1.79

Step-by-step explanation:

the way you wrote the question is questionable

4 0
3 years ago
What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
Question 5(Multiple Choice Worth 1 points) (02.01 LC) Which of the following tables represents a function?
Sergio039 [100]
D (the last option)

x 2 -2 4 -4
y 8 8 12 12

because the x values should not repeat for the y values.
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=16y%20%5E%7B5%7D%20-%2012y%20%5E%7B4%7D%20%2B%204y%20%5C%5C%20%5C%5C%2064%20a%20%5Ctimes%20%5E
Shkiper50 [21]

Answer:

see explanation

Step-by-step explanation:

Assuming you require to factorise the expressions

16y^{5} - 12y^{4} + 4y ← factor out 4y from each term

= 4y(4y^{4} - 3y³ + 1)

--------------------------------

64ax² - 49ay² ← factor out a from each term

= a(64x² - 49y²) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

64x² - 49y²

= (8x)² - (7y)²

= (8x - 7y)(8x + 7y)

then

64ax² - 49ay² = a(8x - 7y)(8x + 7y)

7 0
1 year ago
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