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Zielflug [23.3K]
2 years ago
10

PLEASE ANSWER FAST!!

Mathematics
2 answers:
Masja [62]2 years ago
4 0
The answer to this is 12
sleet_krkn [62]2 years ago
4 0

Answer:

12

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We are given the following information in the question:

y = \sqrt{x}

Differentiating y with respect to x:

\displaystyle\frac{dy}{dx} = \frac{1}{2\sqrtx}

At x = 1

\displaystyle\frac{dy}{dx}\Bigr|_{\substack{x=1} }= \frac{1}{2\sqrt{1}}=\frac{1}{2}

y(1) = \sqrt{1} = 1

Equation of tangent:

(y-y_0) = \displaystyle\frac{dy}{dx}(x-x_0)

Putting the values:

(y-y(1)) = \displaystyle\frac{dy}{dx}\Bigr|_{\substack{x=1} }(x-1)\\\\y - 1= \frac{1}{2}(x-1)\\2y -2 = x - 1\\x-2y+1=0  

The above equations are the required equation of the tangent.

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Step-by-step explanation:

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