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Morgarella [4.7K]
2 years ago
12

Please help me with this question pls, I really need help

Mathematics
1 answer:
Inessa [10]2 years ago
4 0
Answer: x=7, y=-23
(7,-23)

Explanation:

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Which of the following is a proper fraction 7/6 4/3 1/2 3/3
astraxan [27]
1/2 is the proper fraction.
7 0
3 years ago
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The display below shows the number of home runs hit by six of the players on the Cardinals baseball team.
Ket [755]

Answer:

8

Step-by-step explanation:

If each baseball= 4 homeruns, and Chester has 5 baseballs next to his name (20 homeruns), then Evan hit 12 home runs because 4*3= 12 and he has 3 baseballs next to his name.

20-12=8

6 0
3 years ago
Lou wants to make a coffee mixture to sell. He is going to mix Sumatra coffee which costs $2.50 per pound with Columbian coffee
Scilla [17]
To answer this question you need to create 2 equations:
S+C=50
2.50S+3.75C=3.35*(50) 
S=50-C -so now you can plug in S into the second equation
2.50*(50-C)+3.75C=167.5
Now you just need to solve this equation, the final answer will be 34 pounds of colombian coffee and 16 pounds of sumatra coffee 
5 0
3 years ago
Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

5 0
2 years ago
Let y(????)y(t) be a solution of y˙=17y(1−y7)y˙=17y(1−y7) such that y(0)=14y(0)=14. Determine lim????→[infinity]y(????)limt→[inf
shtirl [24]

Answer:

Step-by-step explanation:

Given that,

y' = 17y ( 1-y^7)

Let y=1

Then, y' = 0 for all t

Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.

So, the graph solution will be

y(0) = 1 and this will be an horizontal line

If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.

Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.

So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.

This make the limit be 1.

This shows that x = 1 is a stable equilibrium.

6 0
3 years ago
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