Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions 
and 
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 
shown in purple, then we can plot the second one 
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
11 is the only prime number. It's only multiples are 1 and itself
Answer:
3x - 13 +58 = 90, so 3x +45 = 90
Then 3x = 90 - 45 = 45 and x= 45/3 = 15.
m∠MNQ = 3x-13 = 3(15) - 13
= 45-13
= 32
Well, seeing as how she mixed the clay, she has a total of 2 2/8 pounds clay (unsimplified). Although we don't know how many students she has in one class, with simple division of this number we can figure out how many student can finish the project. Removing the 2/8, we can already tell 2 students can do it, so that's a start. Now to divide the 2 pounds into 8ths. Each pound is enough for 8 students, so the 2 pounds totals to 16. Now add the extra 2 students, it's 18 total students. Hope I explained it well enough!
Answer:
I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots
Step-by-step explanation:
have a happy holidays!
