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Marta_Voda [28]
3 years ago
13

What is the negative solution for x(x+4)=0 ?

Mathematics
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

x = -4

Step-by-step explanation:

x(x + 4) = 0

x = 0   ; x + 4 = 0

                 x = 0 - 4

                 x = -4

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Answer:

\theta_{CAB}=128.316

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Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

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it is to be noted that:

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the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

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\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

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\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

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