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3 years ago

6

I need all the points marked

1 answer:

tatuchka [14]3 years ago

6 0

How to write the co-ordinates

If a point is x units away from origin horizontally and y units away from origin vertically then the co-ordinates are written in the form of (x-co-ordinates,y-coordinates)

Now write

D(2,0)
C(0,7)
B(-8,-4)
A(-6,7)

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Simplify : 3x(x+5)-12+4x

WINSTONCH [101]

The answer is 3x^2 + 19x - 12.

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4 years ago

Use m for the number of monkeys and e for the number of elephants. In a zoo, there are 5 times as many monkeys as there are elep

Thepotemich [5.8K]

Well I would guess there are 5 times as many monkeys? I need more details and also just take it like this if there are 2 elephants theres 10 monkeys 3 elephants 15 monkeys.

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3 years ago

Read 2 more answers

The area of a circle is 36 n cm2?.

jok3333 [9.3K]

Answer:

R = 6

Step-by-step explanation:

Remember... Circle area is:

A = pi×R^2

Where R is the circle radius.

Then,

Pi×R^2=36×Pi

R = square root of 36

R = 6

6 0

3 years ago

The slope of the line is -5/7. Write a point-slope equation of the line using the coordinates of the labeled point

mestny [16]

Answer:

The answer is C.

Step-by-step explanation:

The formula to find equation is y - y1 = m(x - x1).

Let (x1,y1) be (6,2) and m is -5/7.

So the equation is,

y - 2 = -5/7(x - 6)

3 0

4 years ago

Part E<br>Solve the equation x^2- 4x + 6 = 0 by completing the square.

dalvyx [7]

Answer:

Roots for the given polynomial p(x) is x = (2 + √2i) or x = (2 - √2i)

Step-by-step explanation:

Here, the given polynomial is $P(x) = x^{2} - 4x + 6 = 0$

Now, in <u>COMPLETING THE SQUARE</u> there are various steps.

Step (1): HALF THE COEFFICIENT OF x

Here, the coefficient of x = (4) so , the half of 4 = 4/ 2 = 2

Step(2) :Square it ADD IT ON BOTH SIDES OF EQUATION

The square of 2 is $(2)^2$ .

Adding it on both sides of the polynomial, we get

$P(x) : x^{2} - 4x + 6 + (2)^2 = 0 + (2)^2$

Step (3): Use the ALGEBRAIC IDENTITY and make a complete square.

Now, using the identity $(a\pm b)^2 = a^2 + b^2 \pm 2ab$

$\implies x^{2} - 4x + 6 + (2)^2 = 0 + (2)^2\\= (x^{2} - 4x + (2)^2 )+ 6 = 0 + (2)^2\\= (x-2)^2 + 6 - (2)^2 = 0\\\implies (x-2)^2 + 2 = 0$

or, $(x-2)^2 = -2$

Rooting both sides, we get

$\pm (x-2) = (\sqrt2i)$

Solving this, further,we get

x = 2 + √2i , or x = x = 2 - √2i

Hence, roots for the given polynomial p(x) is x = 2 + √2i or x = 2 - √2i

5 0

3 years ago