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Rasek [7]
2 years ago
10

CAN SOME ONE HELP?!!!!!!

Mathematics
2 answers:
Luda [366]2 years ago
7 0
18 with a exponent of 8, for the first one
larisa86 [58]2 years ago
3 0

Step-by-step explanation:

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Helpppp<br> khan academy
larisa [96]

Answer:CA, BC, BA

Step-by-step explanation:

7 0
3 years ago
Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer
denis-greek [22]

Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.


Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave.  You get $16.40.  Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

3 0
3 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t
damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0
2 years ago
68 increased by 75%
mash [69]

Let's see -

Follow the directions below to get your answer -

0.75 × 68 = 51

51 + 68 = 119

So, 119 is your answer

68 increased by 75% is 119.

↑   ↑   ↑  Hope this helps! :D


3 0
3 years ago
Read 2 more answers
The employees of two companies were asked how many times they checked their email during weekends. The table below shows the num
tekilochka [14]
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75

Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75

Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
3 0
3 years ago
Read 2 more answers
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