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NemiM [27]
3 years ago
5

Write the slope intercept form of the equation graphed.

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

yellow

Step-by-step explanation:

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1. Students who attended a track and field meet were polled, and 75% of them said that track and field meets are more fun to att
IRINA_888 [86]

Answer:

Part 1: It is not a valid conclusion to say that track and field sports are more popular than soccer based on the survey. The survey was taken at a track and field event so the people that were surveyed are probably biased.

Part 2: A better way of determining which sport is more popular is by counting how many people show up to each event and comparing the results.  

6 0
3 years ago
I do not know what to put and this was due yesterday
atroni [7]

Answer:

Your answer will be x=2

Step-by-step explanation:

Five plus 6 times a number is equal to 21 minus 2 times the number

Your equation is this:

5+6x=21-2x

Subtract 6x from both sides

5+6x-6x=21-2x-6x

5=21-8x

subtract 21 on both sides

5-21=21-21-8x

-16=-8x    Divide -8 on both sides

2=x

Hope this helps :)

8 0
3 years ago
Please help @musiclover10045<br> I have been stuck on this problem like forever
Stella [2.4K]

a) ABD and CBD are Supplementary angles and need to equal 180 degrees

Subtract 117 from 180 for CBD:

CBD = 180 - 117 = 63 degrees


b) In triangles the the shortest side would be opposite the shortest angle.

Since angle D is 56 degrees ( the smallest inside angle) then side BC would be the shortest side.


c) The side opposite the largest angle would be the longest.

Angle B is 63 degrees ( the largest) so side CD is the longest.


3 0
3 years ago
5/8 divided by 7/10 for the lowest fraction
o-na [289]

Answer:

5/8 ÷ 7/10 = 25/28

Uh i believe this is the lowest fraction it can go to

7 0
3 years ago
Read 2 more answers
A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=
Dahasolnce [82]

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

\phi =\frac{q}{\epsilon _{0}}

where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.

3 0
3 years ago
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