Answer:
Not sure how answer that bc I can't really see it that well but I hope that you get your answer!!
Answer:
(x^2+y)x^3 y^5
Step-by-step explanation:
(x^2 + y)x^4 y^3 / x y^2
(x^2 + y)x^4 - 1 y^3 * y^2
(x^2 + 7)x^3 y^3 * y^2
(x^2 + y)x^3 y^3 +^2
(x^2 + y)x^3 y^5
Answer: 3/8
Step-by-step explanation:
Since it is a fair coin, then generally, P(Head) = P(Tail) = ½
And since we've been asked to find the probability that the number of heads in the first two tosses be equal to the number of heads in the second two tosses, tossing a fair coin four times, the possible outcomes of having equal number of heads in first two tosses and second two tosses becomes:
[HHHH] or [HTHT] or [THTH] or [TTTT] or [HTTH] or [THHT]
=[½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½]
=1/16 * 6
=6/16
=3/8.
