1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
butalik [34]
2 years ago
15

If sin theta = 1/3 and tan theta < 0, what is the value of cos theta?

Mathematics
1 answer:
STatiana [176]2 years ago
5 0
If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).

sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3

We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)

cos Ф=(-2√2) / 3 this solutions is right.

answer:B. -2 square root 2 /3    (or    (-2√2) /3  )
You might be interested in
14,219.92 The 9 in the ones place is _______ the value of the 9 in the tenths place.
Elza [17]

Answer:

less

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the value of x needed to make the equation True. 3/4(20x-8)-3=54
olasank [31]

Answer:

The answer is option B, x = 4.2

6 0
2 years ago
2x + 8y = 6<br> -5x - 20y = -15
kodGreya [7K]

Answer:

The total would be 40.53

Or

Solve for the first variable in one of the equations, then substitute the result into the other equation.

x  =  3  −  4 y

Step-by-step explanation:

This question is incomplete so

7 0
2 years ago
Solve for the positive value of x: 6x2 – 54 = 0
n200080 [17]
If you would like to solve for the positive value of x, you can do this using the following steps:

6 * x^2 - 54 = 0      /6
x^2 - 9 = 0
(x - 3) * (x + 3) = 0
1. x = 3
2. x = - 3

The correct result would be x = 3.
4 0
3 years ago
Simplify: −√16x^2 , when x&lt;0
Savatey [412]

Answer:

-4|x|

Step-by-step explanation:

To simplify :

-\sqrt{16x^2} , when x

In order to simplify the given expression we will take the square root of the term inside the root.

The term in the square root are perfect squares (square of an integer), so, we can write them in square of the numbers.

⇒ -\sqrt{(\pm4x)^2}   [As (\pm4x)^2=16x^2]

On taking square root the square gets removed. So, we have,

⇒ -(\pm4x)

⇒ -4|x|

Since x, so the value would be negative.

So, simplified answer is

-4|x|  (Answer)

3 0
3 years ago
Other questions:
  • Which of the following statements is true?
    10·2 answers
  • Analyze the diagram below and complete the instructions that follow.
    15·1 answer
  • Explain when it might be more efficient to use the percent equation rather than the percent proportion.
    8·1 answer
  • You worked from 8:30am - 2:15pm with a 12 hour lunch break. How long did you work?
    11·1 answer
  • Pls help me answer this if ur good at algebra. Thanks .
    12·2 answers
  • PLZZ HELP ME I WILL GIVE BRAINLIEST TO RIGHT ANSWER​
    11·2 answers
  • Find the length of a segment in the coordinate plane with endpoints (-1 , 3) and (4 , -5).
    9·2 answers
  • Would you use SSS or SAS to prove the triangles​ congruent? If there is not enough information to prove the triangles by SSS or​
    7·1 answer
  • Which one is the answer
    10·2 answers
  • If two angles have the same angle measure, then they are said to be____.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!