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DaniilM [7]
3 years ago
14

What is the result of subtracting the second equation from the first? -2x+y=0 -7x+3y=2

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0

Answer:

If you subtract -2x+y=0 and -7x+3y=2 you will get 5x-2y=-2

Step-by-step explanation:

Subtract -2x and -7x which is 5x

Subtract y and 3y which is -2y

Subtract 0 and 2 which is -2

Result: 5x-2y=-2

Hope this helps!

ohaa [14]3 years ago
3 0

Answer:

The answer is 5x-2y=-2

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3 years ago
I really need help . z = m - x, for x , i have tried x=m-z and thats incorrect.
ch4aika [34]

z = m - x

To solve for x, we can treat this like a typical algebraic problem.

We need to isolate x on one side.

<em><u>Add x to both sides</u></em>

z + x = m

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This should be the answer.

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4 years ago
The length of a rectangle is 2 cm longer than its width. If the perimeter of the rectangle is 56 cm, find its length and width.
Oliga [24]

Answer:

Width = 13 Length = 15

Step-by-step explanation:

2+w=l

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4w+4=56

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7 0
3 years ago
What are the three coordinates that need to be plotted?
Maurinko [17]

Answer:

Step-by-step explanation:

y=2*|x-3|+2

y=|2*x-2*3|+2

y=|2x-6|+2

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y=2x-6

x | 2 | 3 |

y | -2| 0 |

2)

y=|2x-6|

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y=|2x-6|+2

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4 0
2 years ago
The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3
Vesna [10]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\&#10;\boxed{(x-4)^2+y^2=12}
8 0
3 years ago
Read 2 more answers
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