Ismail school is at the corner of high Street and second Avenue. The corner forms a right angle. How might he describe the way t
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Let one length be x and the other be y
x + x + y + y = 440
2x + 2y = 440
Divide by 2 through ...
x + y = 220
y = 220 - x
Area = xy
Area = x(220 -x) = 220x -
Given that that max length of x will be -b/2a
a = -1 b = 220
x =
= 110
x = 110
y = 220 - 110 = 110
Therefore max area = 110 x 110 = 12100 square yards
x + x + y + y = 440
2x + 2y = 440
Divide by 2 through ...
x + y = 220
y = 220 - x
Area = xy
Area = x(220 -x) = 220x -
Given that that max length of x will be -b/2a
a = -1 b = 220
x =
x = 110
y = 220 - 110 = 110
Therefore max area = 110 x 110 = 12100 square yards