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3 years ago

Find the perimeter please

Mathematics

1 answer:

dezoksy [38]3 years ago

4 0

Answer:

56 m

Step-by-step explanation:

5 on the top side short

5+7 on the left side

5+11 on the bottom side

7 on the bottom right side

11 on the long top side

5 on the top right side

so 5+(5+7)+(5+11)+7+11+5

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Help, with solving rational equations! I am no good at it :( Solve for x: 2 over 5 plus 3 over 5 x equals quantity x plus 5 over

mamaluj [8]

If this is your equation: $\frac{2}{5} + \frac{3}{5x} = \frac{x+5}{10}$
Solution:
LCD for 5 and 5x is 5x
$\frac{x}{x} ( \frac{2}{5} )+ \frac{3}{5x} = \frac{x+5}{10}$
$\frac{2x}{5x} + \frac{3}{5x} = \frac{x+5}{10}$
$\frac{2x+3}{5x} = \frac{x+5}{10}$
$10(2x+3)=5x(x+5)$ ←cross product
20x + 30 = 5x² + 25x ←simplify with distributive property
0 = 5x² + 5x - 30 ←use inverse operations to collect all terms on one side
0 = x² + x - 6 ←if possible divide by numerical GCF (This case 5)
0 = (x + 3)(x - 2) ←Factor
x = -3 or x = 2
Please check by substitution in original equation... Both work

4 0

4 years ago

Help asapppp I’ll give brainliest

r-ruslan [8.4K]

Answer:

1. .002

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3. .10

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3 0

3 years ago

Read 2 more answers

Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form

ad-work [718]

Answer:

$\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}$

Step-by-step explanation:

$(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x$

6 0

4 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

How do you write the algebraic notation when the scale factor is 1/2?

PIT_PIT [208]

Answer:

(x,y) = (.5x,5y)

Step-by-step explanation:

7 0

3 years ago

Find the perimeter please ​

Find the perimeter please