Answer:
2.46
Step-by-step explanation:
Cross multiply again
Hope this helps!
Answer: 0.15km/min and 0.3km in 2 mins
Step-by-step explanation:
Given Data:
Cyclists speed = 9km/hr
1. Some traveling 60 km/h is traveling one km/min
60/60= 1 km/min
Rate in km/min
= 9km/hr / 60min
= 3/20 km/min
= 0.15 km/min
Kilometers travelled in 2mins
= 2 / 60
= 1 / 30
= 9km/hr * 1 / 30
= 9 / 30
= 0.3 km in 2mins
Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
The GCF of 18 and 30 is 6
Answer:
1 exponential decay and 78%