Answer:
cymath.com
Step-by-step explanation:
you can solve other equations there as well
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
PEMDAS so you do 3*4 which equals 12, then you add 8=20 20/2=10
Answer:
m
Step-by-step explanation:
m