All categories

3 years ago

Simplify the square root of 27x^12/300x^8

Mathematics

1 answer:

serg [7]3 years ago

7 0

Answer:

(3/10) * (x ^ 2)

Step-by-step explanation:

The first thing we are going to do is rewrite the expression correctly.

We have:

root (27x ^ 12 / 300x ^ 8)

Rewriting:

root ((27/300) * (x ^ 12 / x ^ 8))

root ((9/100) * (x ^ (12-8)))

root ((9/100) * (x ^ (4)))

3 * x ^ 2 * root ((1/100)

(3 * x ^ 2) / 10

(3/10) * (x ^ 2)

You might be interested in

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0

1 year ago

Solve for N: 3n - 7 = 6n - 2n

jonny [76]

Answer:

-7

Step-by-step explanation:

1. Combine Like Terms

3n-7=4n

2. Subtract 3n on both sides.

-7=n

3. You got your answer:)

3 0

2 years ago

Stephanie has a homeowners insurance policy for her $355,000 home with an annual premium of $0.42 per $100 of value and a deduct

frosja888 [35]

Answer:

$0.28 per 100 of value (B)

Step-by-step explanation:

Stephanie has a homeowner insurance policy of $355,000

Annual premium = $0.42 per 100

There is a deductible of $500

Stephanie has an annual out of pocket expense of

[($355,000/100) x $0.42] + $500 = $1,991

From the question, Stephanie now wants a new deductible amount of 1000.

Let X be the new annual premium

[(355,000X) / 100] + 1000 = 1991

3550X + 1000 = 1991

3550X = 1991 -1000

3550X = 991

X = 991/3550

X = 0.2791

X = 0.28 ( approximately)

The new annual premium is $0.28 per 100 of value

5 0

3 years ago

Find the output, h, when the input, x, is - 18.<br><br> h=17+ x/6

Nookie1986 [14]

Answer:

h = 20

Step-by-step explanation:

h = 17 + x/6

h = 17 + (18) / 6

h = 17 + 3

h = 20

5 0

2 years ago

Read 2 more answers

Can anyone help me please? it’s urgent.

katrin [286]

It said "no association between this dude winning and loss in harsh condition"

now look at harsh condition, total is 20, since there is no association that means they are the same, which is 10 and 10

WIN column total is 168, 158 for normal condition, 10 for harsh condition, adds up to 168.

LOSS column total is 72, 62 for normal condition and 10 for harsh condition, adds up to 72.

if u wana check if it adds up with Normal Condition, 62 plus 158 is 220.

checked, complete, this is david signing off

8 0

2 years ago