Find a quadratic equation whose roots are -3 and 5. NO LINKS PLZ!!!!!

In the diagram, point P is a point of tangency. Find the radius r of circle O.

vlabodo [156]

Answer:

r = 12

Step-by-step explanation:

From the figure attached,

QP is a tangent to the circle O at the point P.

Therefore, by the property of tangency,

OP ⊥ QP

By applying Pythagoras theorem In right triangle QPO,

(Hypotenuse)² = (Leg 1)² + (Leg 2)²

(OQ)² = (OP)² + (PQ)²

(25 + r)² = (35)² + r²

625 + r² + 50r = 1225 + r²

50r = 1225 - 625

50r = 600

r = 12

Therefore, r = 12 units is the answer.

4 0

3 years ago

PLEASE RESPOND! !!

cestrela7 [59]

Answer:

36/132

Step-by-step explanation:

36/132, .27, 27%...

6 0

3 years ago

1. What is the solution to the equation below? -5/4x + 2/5 = -13/30

Artemon [7]

Answer:

2/3 or .6 repeating

Step-by-step explanation:

6 0

3 years ago

What is the lmc of two numbers that have no common factors greater then 1

Luba_88 [7]

We can take prime numbers so they don't have a common factor other than 1.

3, and 5.

So we have to list the multiples to find the LCM

3: 3, 6, 9, 12, 15, 18
5: 5, 10, 15, 20, 25

15 is the LCM of 3 and 5

So, you can notice that if two numbers, lets call them a and b, have no common factor, then $a \times b$ is the LCM.

Hope that helped :)

6 0

4 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago