Answer:
You plot the points on graph according to the the table
Once you plotted every point on the table, you connect the dots.
Example: Jan (Month) Go Up To 44 , Feb(Month) Go Up 40
I HOPE I HELP AS MUCH AS POSSIBLE
Answer:
700 mL of ethanol would be added
Explanation:
Given data:
Volume of ethanol added to make 40% v/v solution = ?
Total volume of solution = 1750 mL
Solution:
We will calculate the 40% 1750 mL which will be the volume of ethanol added to the water to make 40%v/v solution.
(40/100)× 1750 mL
0.4 × 1750 mL
700 mL
700 mL of ethanol would be added.
Answer:
There are 1.205x10²³ particles in 0.2 moles.
Explanation:
In order to <u>convert from moles to number of particles</u> we need to use <em>Avogadro's number</em>, which states the number of particles contained in 1 mol:
- 0.2 mol * 6.023x10²³ particles /mol = 1.205x10²³ particles
Thus, there are 1.205x10²³ particles in 0.2 moles.
Answer:
3.2 g of O₂
Solution:
This reaction is for the formation of Potassium Superoxide, The reaction is as follow,
K + O₂ → KO₂
First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
39.098 g (1 mole) K produced = 71.098 g of K₂O
So,
3.91 g of K will produce = X g of K₂O
Solving for X,
X = (3.91 g × 71.098 g) ÷ 39.098
X = 7.11 g of K₂O
Hence, it is confirmed that we have selected the right equation,
So,
As,
39.098 g of K required = 32 g of O₂
So,
3.91 g of K will require = X g of O₂
Solving for X,
X = (3.91 g × 32 g) ÷ 39.098 g
X = 3.2 g of O₂
Becuz the sun refelt off the earth and on to the moon.