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1 year ago

Q+ is an ion of element Q. What has the highest value in the ion?

Chemistry

1 answer:

Firdavs [7]1 year ago

7 0

The highest value of the ion is the nucleon number. The correct option is a.

<h3>What is nucleon number?</h3>

The mass number of an element is so named because it represents the total number of protons and neutrons in the element.

The total number of protons and neutrons in an atomic nucleus is known as the mass number, also known as the atomic mass number or nucleon number. It is roughly equivalent to the atomic mass expressed in atomic mass units.

In the given ion Q+, the nucleon number has the highest value in the ion

Thus, the correct option is a.

For more details regarding nucleon number, visit:

brainly.com/question/14622763

#SPJ1

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What is the compound name for NF

dlinn [17]

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(If you mean by a gas of some sort)

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3 years ago

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Particles of Substance X are dispersed in water to form a colloid. Which describes the electrical charges on the particles of Su

Novay_Z [31]

The correct answer is option A.

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All the particles of substance X will have same charge on its surface, which is balanced by the oppositely charged ions in the water.

For example, soap solution (sodium palmitate) dissociates into ions:

C₁₅H₁₁COONa --> C₁₅H₁₁COO⁻ + Na⁺

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3 0

3 years ago

Given:

bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ $= \frac{59.7}{16} = 3.73125 \ moles$

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

5 0

3 years ago

How many moles of solute are in 250.0 mL of a 3.00 M HCl solution?

cestrela7 [59]

0.250 L*3M=0.250 L*3mol/L= 0.750 mol

8 0

3 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.

lubasha [3.4K]

Answer:

Pressure, P = 67.57 atm

Explanation:

<u>Given the following data;</u>

Volume = 0.245 L
Number of moles = 0.467 moles
Temperature = 159°C
Ideal gas constant, R = 0.08206 L·atm/mol·K

<u>Conversion:</u>

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.

Making P the subject of formula, we have;

$P = \frac {nRT}{V}$

Substituting into the formula, we have;

$P = \frac {0.467*0.08206*432}{0.245}$

$P = \frac {16.5551}{0.245}$

<em>Pressure, P = 67.57 atm</em>

4 0

3 years ago