Subtract the mass of the solute from the whole solution volume.
Molarity, percent by mass, and percent by volume are all ways to represent concentration.
By dividing the number of moles by the number of liters of water utilized in the solution, we can compute the molar concentration. Here, for instance, 1.25 L of water has entirely dissolved the acetic acid. In order to determine the molar concentration, which is 0.1332 M, divide 0.1665 moles by 1.25 L. A titration is a method for figuring out the concentration of an unknown solution by using a solution with known concentration.
Finding the concentration for each sample's absorbance on the standard curve is the first step in calculating the sample concentration based on the standard curve. The next step is to multiply the concentration by the dilution factor for each sample.
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Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
In this question, the sulfur atom has atomic number 16 and atomic mass 33. The Atomic number represents the number of the proton inside the atoms and atomic mass represent the mass of the atoms. Since electron mass to small, the atomic mass can be interpreted as the sum of neutron and proton. Then, the number of the neutron would be:
mass= neutron + proton
33= neutron+16
neutron = 17
Answer:
it is technically biological weathering but mechanical works as well
Answer:
Reduction involves a half-reaction in which a chemical species decreases its oxidation number, usually by gaining electrons. The other half of the reaction involves oxidation, in which electrons are lost. Together, reduction and oxidation form redox reactions (reduction-oxidation = redox).
Explanation:
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