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Anna71 [15]
3 years ago
13

Help please, my brains is empty :o(

Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Answer:

I think 5 and 5 are equal so the angles are equal which are 70,70

Step-by-step explanation:

70+70+x=180

140+x=180

x=40

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What is the range of f? ​
Andrew [12]

Answer:

[-4,5]

Step-by-step explanation:

you look on the starting point and the ending point of the y-axis ( you always start with the smallest value)

7 0
2 years ago
The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
Read 2 more answers
Simplify the algebraic expression by combining like terms 0.8x + 19 - 0.7x
Arte-miy333 [17]

Answer:

Let's simplify step-by-step.

0.8x+19−0.7x

=0.8x+19+−0.7x

Combine Like Terms:

=0.8x+19+−0.7x

=(0.8x+−0.7x)+(19)

=0.1x+19

Answer:

=0.1x+19

Step-by-step explanation:

I hooe it helps plz Mark me brainliest

8 0
3 years ago
Rohan is checking in poodles for a dog show. A miniature poodle must be between 10 in. and 15 in. at the shoulder. The body leng
Masteriza [31]
The first one, the fourth one, and the middle one
 
3 0
3 years ago
Read 2 more answers
State the number of complex roots, the number of positive real roots and the number of negative real roots of
harkovskaia [24]

9514 1404 393

Answer:

  • 2 complex roots
  • 2 positive real roots
  • 0 negative real roots

Step-by-step explanation:

The signs of the terms are + - - +. There are two sign changes, so 0 or 2 positive real roots.

Negating the signs of the odd-degree terms, the signs are + + + +. There are no sign changes, so 0 negative real roots.

For x=0, the value of the quartic is +3. For x=1, the value is -3, so we know there are 2 positive real roots, one of which lies in the interval (0, 1).

The 4th-degree polynomial equation must have 4 roots, so the other two must be complex.

  • 2 complex roots
  • 2 positive real roots
  • 0 negative real roots

_____

The roots are approximately 0.489999841592, 2.06573034434, −0.777865092969 ± 1.53582061225i

8 0
2 years ago
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