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k0ka [10]
3 years ago
8

PLEASE I NEED HELP ASAP

Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer:

<em>19 </em>

Step-by-step explanation:

(4d - 1)° + 105° = 180°

4d - 1 + 105 = 180

4d = 76

d = <em>19</em>

Lubov Fominskaja [6]3 years ago
7 0

Answer:

19

Step-by-step explanation:

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The degree is the highest power so
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3 years ago
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49.5 is what percent of 33
Svet_ta [14]



  49.5 over 33 and X over 100 cross multiply so multiply 33 by x you get 33x then multiply 100 by 49.5 you get 4,950 then divide 4,950 by whatever is in front of X so 33 4,950 divided by 33 equals 150%
49.5/33   X/100   49.5x100= 4,950    33* x = 33x  4,950/33=150
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6 0
3 years ago
Explain how to isolate the variable in the equation -2/3n + 7 = 15
vodka [1.7K]

Answer:

n = -12

Step-by-step explanation:

(-2/3)n + 7 = 15          

(-2/3)n+7-7 = 15-7               Subtract by 7 on both sides

(-2/3)n = 8                         Multiply by the reciprocal of the fraction, which is                                                                                                  

(-2/3)n*(-3/2) = 8(-3/2)      This makes it so you get n *1 and isolates n.

n = -24/2 = -12

7 0
3 years ago
Please help with this word problem
Illusion [34]
Comment
There is no exact answer to this. It will have to shown in terms of the width. Also we need to use the Pythagorean Formula

Givens
L = 10 * W
W = W

Formula
L^2 + W^2 = C^2

Solution
(10W)^2 + (W^2) = C^2
C^2 = 100W^2 +W^2
C^2 = 101W^2                   Now take the square root.
C = sqrt(101W^2)
C=  W*sqrt(101)                <<<<< Answer. I think this is what they mean
7 0
3 years ago
Exercises gives the positions s = f(t) of a body moving on a coordinate line, with s in meters and t in seconds.
SashulF [63]

Hi there!

a. Find the displacement by plugging in the values of the interval:

f(2) - f(0) = 0 - 2 = -2 meters.

Average velocity is the slope, thus:

v_{avg} = \frac{f(2) - f(0)}{2 - 0} = \frac{0 - 2}{2 - 0} = -1

The average velocity for the interval is -1 m/s.

b. To find the speed at the endpoints, we must take the derivative to get the velocity equation:

f(t) = t² - 3t +2

f'(t) = 2t - 3, at t = 0, speed = |-3| = 3 m/s. At t = 2, speed = 2(2) - 3 = 1 m/s.

Acceleration is the second derivative, thus:

f''(t) = 2. The acceleration is 2 m/s² for both endpoints.

c. When the body changes direction, the first derivative changes signs. Thus:

0 = 2t - 3

3 = 2t, t = 1.5 sec. This is where the body changes direction.

8 0
3 years ago
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