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2 years ago

Amy crashed her bike into the fence. She was thrown over it onto the lawn. Which Newton law applies

Physics

1 answer:

BlackZzzverrR [31]2 years ago

7 0

Answer:

Newton's First Law of Motion applies here.

Explanation:

Before crashing into the fence, Amy was moving at a certain speed on her bike. As, she crashed her bike into the fence, the collision stopped the bike suddenly. But, Amy had the same speed due to inertia of her body. Due tot his speed Amy did not stop and she was thrown over the fence onto the lawn. So, the force of inertia of Amy's body caused her to be overthrown in this case. We study about inertia in Newton's First Law of Motion, which is also known as Law of Inertia.

<u>Newton's First Law of Motion applies here.</u>

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In the process of melting, what best describes what happens to a solid?

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2 years ago

In magazine car tests an important indicator of performance is the zero to 60 mph (0 to 96.6 km/h) acceleration time. A time bel

slavikrds [6]

Answer:

2.73414 seconds

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Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

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$v=60\times \dfrac{1609.34}{3600}=26.822\ m/s$

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$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{26.822-0}{9.81}\\\Rightarrow t=2.73414\ s$

The time taken is 2.73414 seconds

The potential energy is given by

$U=mgh\\\Rightarrow U=1300\times 9.81\times 36.66766\\\Rightarrow U=467622.66798\ J$

The change in potential energy is 467622.66798 J

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2 years ago

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My answer -

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2 years ago

A cyclotron is to accelerate protons to an energy of 5.4 MeV. The superconduction electromagnet of the cyclotron produces a 2.9T

mart [117]

<h3><u>Answer;</u></h3>

Radius = 0.0818 m

Angular velocity = 2.775 × 10^7 rad/sec

<h3><u>Explanation;</u></h3>

The mass of proton m=1.6748 × 10^-27 kg;

Charge of electron e= 1.602 × 10^-19 C;

kinetic energy E= 2.7 MeV

= 2.7 × 10^6 × 1.602 × 10^-19 J;

= 4.32 × 10^-13 Joules

But; K.E =0.5m*v^2,

Hence v=√(2K.E/m)

Velocity = 2.27 × 10^7 m/s

Angular velocity, ω = v/r

Therefore; V = ωr

Hence; V = √(2K.E/m) = ωr

r= √(2E/m)/w = √E*√(2*m)/(eB)

= √E * √(2×1.6748×10^-27)/(1.602×10^-19 ×2.9)

but E = 4.32 × 10^-13 Joules

r = 0.0818 m

Angular speed

Angular velocity, ω = v/r , where r is the radius and v is the velocity

Therefore;

Angular velocity = 2.27 × 10^7 / 0.0818 m

= 2.775 × 10^7 rad /sec

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