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shusha [124]
2 years ago
15

You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide

s to use a magnetic field produced by current. For your study you decide to use a Cathode Ray Tube (CRT) with a magnetic field perpendicular to its axis. The magnetic field will be produced by Helmholtz coils, two parallel coils of wire with the distance between them equal to their radius. Before you can evaluate the sensitivity of the electron microscope design, you need to determine how the magnitude of a constant magnetic field affects the position of the beam spot.
a. Draw a picture of the CRT in the Helmholtz coils. Since you will not be using electric fields, do not include the deflection plates in your sketch. Be sure you have all the other components in your sketch. Draw a coordinate axis on this sketch and show the magnetic field direction and the region occupied by the magnetic field. Draw the electron trajectory through all regions of the CRT together with its velocity andacceleration. Draw the electron trajectory if there were no magnetic field. The difference between where these two trajectories hit the CRT screen is the deflection.
b. What path does an electron follow while traveling through a constant magnetic field? The magnetic force is always perpendicular to the electron

Physics
2 answers:
rewona [7]2 years ago
4 0

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

r = \frac{mV}{qB}

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

Tju [1.3M]2 years ago
3 0

Answer:

1) see picture

2) ⇒ force = 0

   ⇒ f = evB

3) v = \sqrt{\frac{2e\delta v}{m}}

4) v_m = \frac{eBr}{m}

Explanation:

See attached for detailed workings.

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spin [16.1K]

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Explanation:

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3 years ago
An athlete jumping vertically on a trampoline leaves the surface with a velocity of 8.5 m/s upward. what maximum height does she
Mumz [18]
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8 0
3 years ago
A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm . It carries a current of 1.50 A . Part A How
AleksAgata [21]

Answer:

The number of turns, N = 1750

Explanation:

It is given that,

The inner radius of a toroid, r = 12 cm

Outer radius, r' = 15 cm

The magnetic field at points within the coils 14 cm from its center is, B=3.75\ mT=3.75\times 10^{-3}\ T

R = 14 cm = 0.14 m

Current, I = 1.5 A

The formula for the magnetic field at some distance from its center is given by :

B=\dfrac{\mu_o NI}{2\pi R}

N=\dfrac{2\pi R B}{\mu_o I}

N=\dfrac{2\pi \times 0.14\times 3.75\times 10^{-3}}{4\pi \times 10^{-7}\times 1.5}

N = 1750

So, the number of turns must have in a toroidal solenoid is 1750. Hence, this is the required solution.

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