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shusha [124]
2 years ago
15

You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide

s to use a magnetic field produced by current. For your study you decide to use a Cathode Ray Tube (CRT) with a magnetic field perpendicular to its axis. The magnetic field will be produced by Helmholtz coils, two parallel coils of wire with the distance between them equal to their radius. Before you can evaluate the sensitivity of the electron microscope design, you need to determine how the magnitude of a constant magnetic field affects the position of the beam spot.
a. Draw a picture of the CRT in the Helmholtz coils. Since you will not be using electric fields, do not include the deflection plates in your sketch. Be sure you have all the other components in your sketch. Draw a coordinate axis on this sketch and show the magnetic field direction and the region occupied by the magnetic field. Draw the electron trajectory through all regions of the CRT together with its velocity andacceleration. Draw the electron trajectory if there were no magnetic field. The difference between where these two trajectories hit the CRT screen is the deflection.
b. What path does an electron follow while traveling through a constant magnetic field? The magnetic force is always perpendicular to the electron

Physics
2 answers:
rewona [7]2 years ago
4 0

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

r = \frac{mV}{qB}

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

Tju [1.3M]2 years ago
3 0

Answer:

1) see picture

2) ⇒ force = 0

   ⇒ f = evB

3) v = \sqrt{\frac{2e\delta v}{m}}

4) v_m = \frac{eBr}{m}

Explanation:

See attached for detailed workings.

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You drop your cell phone. Prior to hitting the ground, the phone's kinetic energy will ________ and its potential energy will __
SVETLANKA909090 [29]

Answer:

The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.

Explanation:

The kinetic energy {\rm KE} of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.

The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy {\rm GPE} of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.

5 0
1 year ago
Blank is the the decrease in a materail's volume when it's blank decrease ​
natulia [17]

Answer:

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7 0
2 years ago
Determine the focal length of a plano-concave lens (refractive index n =1.5) with 24 cm radius of curvature on its curve surface
tatyana61 [14]

Answer:

Option 3: -48 cm

Explanation:

We are given:

refractive index; n = 1.5

radius of curvature; r2 = 24 cm

Formula for the focal length is given as;

1/f = (n - 1) × [(1/r1) - (1/r2)]

As r1 tends to infinity, 1/r1 = 0

Thus,we now have;

1/f = (n - 1) × (-1/r2)

Plugging in the relevant values;

1/f = (1.5 - 1) × (-1/24)

1/f = -0.02083333333

f = -1/0.02083333333

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3 0
2 years ago
Jerry runs 60 meters east and then 20 meters west in 10
liraira [26]

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3 years ago
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I think you're saying that once you start pushing on the cars, you want to be able to stop each one in the same time. 

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(And besides, there's no great honor awarded around here for explaining
why any given choice is NOT the answer.)

The answer is momentum.

Momentum is (mass x speed).  Change in momentum is (force x time).

No matter the weight (mass) or speed of the car, the one with the greater
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to stop it.  If the time is the same for any car, then more momentum
will always require more force.


4 0
3 years ago
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