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Aneli [31]
3 years ago
6

Match the property of a sound wave to the correct definition. A. amplitude . B. frequency  . C. period . D. pitch  E. loudness 

Physics
2 answers:
svetlana [45]3 years ago
8 0

Amplitude: How dense the medium is in the compression part of the wave, and how empty the rarefied area is.

Frequency: The number of wavelengths that pass a position in 1 second.

loudness: The quality of the sound that is most closely linked to the amplitude of the sound wave.

Period: The amount of time that it takes one wavelength to pass by a position.

Pitch: The quality of the sound that is most closely linked to the frequency of the sound wave.

Maru [420]3 years ago
5 0

Amplitude: How dense the medium is in the compression part of the wave, and how empty the rarefied area is.

Frequency: The number of wavelengths that pass a position in 1 second.

loudness: The quality of the sound that is most closely linked to the amplitude of the sound wave.

Period: The amount of time that it takes one wavelength to pass by a position.

Pitch: The quality of the sound that is most closely linked to the frequency of the sound wave.

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2 years ago
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
olya-2409 [2.1K]

Answer:

17.1

Explanation:

The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m

The initial speed with which the ranger was driving, u = 11.4 m/s

The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)

The distance required for the ranger to come to rest, s = Required

The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;

v² = u² + 2·a·s

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Where;

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Plugging in the values for 'v', 'u', and 'a', gives;

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6 0
3 years ago
How much work would a child do while puling a 12-kg wagon a distance of 3m with a 22 N force directed 30 degrees with respect to
Alika [10]

Answer:

The work done will be 57.15 J

Explanation:

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W = Fd\cos\theta

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3 years ago
Question 4 of 20
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5 0
2 years ago
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